Introductory General Chemistry  ·  Unit 13

Solutions

Start here if solution problems all seem to use similar words but different math. Building from gas laws, this unit helps you sort the big ideas first: what is dissolved, how concentration is measured, when dilution applies, and when you need full reaction stoichiometry — leading into equilibrium.

What you'll learn

Calculate and convert between molarity, dilution, and solution volumes. Predict and calculate colligative properties including boiling point elevation and freezing point depression. Read solubility curves and apply solubility rules to predict precipitation. Solve solution stoichiometry problems including titration and precipitation reactions.

13.1 Start Here: What a Solution Is and What the Parts Are Called

A solution is a homogeneous mixture. The solute is the substance being dissolved, and the solvent is the substance doing the dissolving.

This vocabulary matters because later calculations depend on it. Mixing up solute, solvent, and solution mass or volume is the most common early mistake — fix that here.

In a solution, the solute is spread evenly throughout the solvent.

"Like dissolves like" is the key rule: polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.

TermDefinitionExample
SoluteSubstance being dissolved (usually smaller amount)NaCl in saltwater
SolventSubstance doing the dissolving (usually larger amount)H₂O in saltwater
Aqueous solutionWater is the solventMost biological fluids
ElectrolyteSolute that dissociates into ions, conducts electricityNaCl → Na⁺ + Cl⁻
NonelectrolyteSolute that stays as molecules, does not conductGlucose, C₆H₁₂O₆

Particle count rule

  • Strong electrolytes (ionic compounds, strong acids/bases) dissociate 100%.
  • Weak electrolytes (weak acids/bases) dissociate partially.
  • Nonelectrolytes do not dissociate at all.
  • This distinction drives colligative property calculations.

13.2 Solubility: Unsaturated, Saturated, or Supersaturated?

Solubility is the maximum amount of solute that can dissolve in a given amount of solvent at a specific temperature.

Do not miss the temperature part. A solution can be saturated at one temperature and unsaturated at another.

To classify a solution, compare the amount dissolved with the solubility limit at that temperature.

Unsaturated — less than the solubility limit is dissolved, so more solute can still dissolve.
Saturated — the dissolved amount is at the solubility limit. Extra solute stays undissolved.
Supersaturated — more than the usual solubility limit is dissolved at that temperature. This state is unstable and can crystallize if disturbed.

Temperature matters: For most solid solutes in water, solubility increases as temperature increases. For gases dissolved in liquids, solubility usually decreases as temperature increases.

13.3 Molarity: Moles per Liter of Solution

The most common concentration unit in chemistry. Molarity expresses moles of solute per liter of solution (not solvent).

This is the concentration idea you will use most in reaction problems. The usual mistake is simple but costly: forgetting to convert mL to L.

Formula
M = mol soluteL solution

Rearrangements you'll use constantly:

mol solute = M × L L solution = molM

Common error

  • Volume must be in liters.
  • Always convert mL → L by dividing by 1000 before plugging in.
  • Also, molarity is moles per liter of solution, not per liter of solvent.

13.4 Dilution: Same Solute, Bigger Volume, Lower Concentration

Dilution is the process of adding solvent to reduce the concentration of a solution. The number of moles of solute stays constant — only the volume increases.

Start here if dilution problems keep fooling you. The key idea is that dilution is not a reaction. No new solute appears and none disappears.

Dilution Equation
C₁V₁ = C₂V₂ C = molarity and V = volume, using the same units on both sides
⚠ Critical Trap: V₂ is the FINAL volume
  • V₂ is NOT the volume of water you added — it's the total final volume of the diluted solution.
  • If a problem says "add 450 mL of water to 50 mL of solution," the final volume V₂ = 500 mL.
  • Always ask: "Is this the total volume, or the volume added?" before plugging in.

13.5 Percent Concentration: m/m, m/v, and v/v

Three common percent-based concentration expressions used in labs and industry:

Notice that the denominator changes depending on the type. The percent sign is easy to remember — what it is actually comparing is where the setup breaks.

TypeFormulaUnitsUse
% mass/mass (% m/m)(g solute / g solution) × 100% (dimensionless)Solid solutes, concentrated acids
% mass/volume (% m/v)(g solute / mL solution) × 100g per 100 mLIV bags, pharmaceuticals
% volume/volume (% v/v)(mL solute / mL solution) × 100% (dimensionless)Alcohol content, mixtures of liquids

Percent reminder

  • Always use g of solution (not solvent) in m/m.
  • Solution = solute + solvent.
  • If 15 g NaCl is dissolved in 135 g water, the solution mass is 150 g.

13.6 Molality: Moles per Kilogram of Solvent

Molality is moles of solute per kilogram of solvent (not solution). It is temperature-independent because it is based on mass, not volume — making it essential for colligative property calculations.

If this feels too similar to molarity, slow down and compare the denominator. That one difference is the whole reason the two units are used in different places.

Formula
m = mol solutekg solvent

These two units look almost the same. The difference is the denominator — and that one difference determines when each unit is used.

PropertyMolarity (M)Molality (m)
DenominatorL of solutionkg of solvent
Temperature dependent?Yes (volume changes)No (mass is constant)
Use forStoichiometry, reactionsColligative properties

13.7 Colligative Properties: Count Particles, Not Chemical Names

Colligative properties depend on how many dissolved particles are present in a given amount of solvent, not on the chemical identity of those particles.

This is where the electrolyte idea from the start of the unit starts to matter. More dissolved particles means a larger effect, which is why the van 't Hoff factor matters.

The three rows below show how particle count multiplies the colligative effect at the same molality.

Same molalityiRelative effect size
1.0 m glucose1baseline
1.0 m NaCl2about 2× larger
1.0 m CaCl₂3about 3× larger

This is the key comparison: at the same molality, the solution that makes more dissolved particles shows the larger colligative effect.

Boiling Point Elevation (ΔTb)
ΔTb = Kb × m × i Kb(water) = 0.512 °C·kg/mol

Solute particles disrupt escape of solvent molecules; more energy needed → higher boiling point.

Freezing Point Depression (ΔTf)
ΔTf = Kf × m × i Kf(water) = 1.86 °C·kg/mol

Solute particles interfere with lattice formation; the solution freezes at a lower temperature. New fp = 0 − ΔTf.

Osmotic Pressure (π)
π = iMRT R = 0.08206 L·atm/mol·K, with T in Kelvin

Pressure needed to prevent osmosis across a semipermeable membrane. Clinically important for IV solutions.

Vapor Pressure Lowering

Adding solute reduces the fraction of solvent molecules at the surface, lowering vapor pressure. Drives both boiling point elevation and freezing point depression.

  • The van 't Hoff factor i = number of dissolved particles per formula unit after dissociation.
  • NaCl: i = 2 (Na⁺ + Cl⁻).
  • CaCl₂: i = 3 (Ca²⁺ + 2 Cl⁻).
  • Glucose: i = 1 (no dissociation).

13.8 Solution Stoichiometry: Turn Concentration into Moles First

Solution stoichiometry uses the same mole ratios as any other stoichiometry problem.

Do not rush past the first move. In solution stoichiometry, the setup almost always starts with mol = M × L. If you skip that, the rest of the problem falls apart.

The first move is to convert solution data into moles using mol = M × L. Then use the balanced equation or net ionic equation to relate those moles to the substance you need.

Step 1 — Convert to moles: use mol = M × L
Step 2 — Use the reaction: apply the balanced equation or net ionic equation
Step 3 — Convert the answer: moles → grams or → volume if needed

For precipitation reactions, identify the insoluble product first.

AgNO₃(aq) + NaCl(aq) → AgCl(s) ↓ + NaNO₃(aq)
Identify the precipitate using solubility rules. Net ionic: Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
Refresher: Stoichiometric Relationships
  • Mole ratios come from the balanced equation — never from molecular masses.
  • For solutions: moles = M × L before and after every stoichiometric step.
  • For limiting reagent in solution: find mol of each reactant, compare with mol ratio.

13.9 Particle Diagrams: What Dissolved Solutions Look Like Microscopically

Particle diagrams show solute and solvent particles at the microscopic level. Key features to represent accurately:

This is where the vocabulary, conductivity ideas, and particle-count ideas all come together. If the diagram is wrong, the chemistry interpretation will be wrong too.

  • Ionic solutes (NaCl): show separate Na⁺ and Cl⁻ ions dispersed through water molecules.
  • Molecular solutes (glucose): show intact molecules, no ions.
  • Insoluble precipitates (AgCl): show solid clusters at the bottom, separate from dissolved ions.
  • Net ionic: spectator ions disappear; only the precipitate and reacting ions remain.

These particle diagrams help you predict three things: whether the solution conducts electricity, how many dissolved particles are present, and whether a precipitate forms.

NaCl(aq) — ions dispersed throughout

Glucose(aq) — intact molecules, no ions

After precipitation — AgCl(s) solid at bottom

Key Na⁺ Cl⁻ Glucose molecule Ag⁺ NO₃⁻ AgCl(s) precipitate
✦ Practice Problems
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Next step after Unit 13

Solutions set up the particle and concentration ideas you need for reversible systems. The next move is chemical equilibrium, where forward and reverse changes compete at the same time.

Introductory General Chemistry · Unit 13 · Solutions